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100% Pass Quiz CDCS - Updated EXIN EPI Certified Data Centre Specialist Exam Duration
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EXIN EPI Certified Data Centre Specialist Sample Questions (Q35-Q40):
NEW QUESTION # 35
The humidity in the computer room has changed from about 50% down to 35% Relative Humidity (RH).
What influence does this have on Electrostatic Discharge (ESD)?
- A. ESD levels will go down
- B. No influence as long as the temperature is at approximately 20°C/77°F
- C. ESD levels will go up
- D. Relative humidity has no influence on ESD
Answer: C
Explanation:
As relative humidity decreases, Electrostatic Discharge (ESD) risks increase. Lower humidity levels reduce the amount of moisture in the air, which normally helps dissipate static charges. When the humidity drops from 50% to 35%, the likelihood of static electricity accumulating on surfaces rises, leading to a higher potential for ESD incidents that could damage sensitive IT equipment.
Detailed Explanation:
ESD events are more common in dry environments because there is less atmospheric moisture to neutralize electrical charges. Maintaining relative humidity above 40% helps minimize the risk of ESD, which is why data centers often control humidity levels tightly to protect equipment from static discharge that could cause hardware failures or data loss.
EPI Data Center Specialist References:
EPI data center best practices stress the importance of maintaining stable humidity levels to prevent ESD, particularly in computer rooms. Recommended humidity ranges are typically above 40% to prevent conditions that would foster static buildup.
NEW QUESTION # 36
You are allowed to use a calculator for this question.
A computer room has a net volume of approximately 2,500 m³ / 88,287 ft³.
The temperature is 20 °C / 68 °F.
The required design concentration is 7%.
The S-Factor is 0.1359 (metric) / 1.885 (imperial).
Calculate the amount of gas required for this computer room based on FM200. What is the correct weight?
- A. Approximately 1,390 kg / 3,000 lbs
- B. Approximately 410 kg / 900 lbs
- C. Approximately 1,640 kg / 3,600 lbs
- D. Approximately 820 kg / 1,800 lbs
Answer: D
Explanation:
The amount of FM200 gas required can be calculated using the formula:
Weight of Gas=Net Volume×Design Concentration×S-Factor ext{Weight of Gas} = ext{Net Volume} imes ext{Design Concentration} imes ext{S-Factor}Weight of Gas=Net Volume×Design Concentration×S-Factor Using metric units:
Net Volume: 2,500 m³
Design Concentration: 7% (or 0.07)
S-Factor: 0.1359
Calculation:
2,500 m3×0.07×0.1359=821.325 kg2,500 , ext{m}